#include #include #include using namespace std; int need[5]; int N, E[40]; int dp[40][5]; int solve(int i, int j){ if(i >= N){ return (j == 3); } if(dp[i][j] != -1)return dp[i][j]; int res = solve(i + 1, j); int jj = j; if(j < 3 && need[j] <= E[i])++jj; res += solve(i + 1, jj); return dp[i][j] = res; } int main(){ memset(dp, -1, sizeof(dp)); cin >> need[0] >> need[1] >> need[2]; cin >> N; for(int i=0;i> E[i]; sort(need, need + 3); sort(E, E + N); cout << solve(0, 0) << endl; return 0; }