#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; inline int toInt(string s) {int v; istringstream sin(s);sin>>v;return v;} template inline string toString(T x) {ostringstream sout;sout< VI; typedef vector VVI; typedef vector VS; typedef pair PII; typedef long long LL; #define FOR(i,a,b) for(int i=(a);i<(b);++i) #define REP(i,n) FOR(i,0,n) #define MP make_pair #define MT make_tuple #define EACH(i,c) for(auto i: c) #define SORT(c) sort((c).begin(),(c).end()) #define ALL(a) (a).begin(),(a).end() #define RALL(a) (a).rbegin(), (a).rend() const double EPS = 1e-10; const double PI = acos(-1.0); #define dump(x) cerr << #x << " = " << (x) << endl; #define debug(x) cerr << #x << " = " << (x) << " (L" << __LINE__ << ")" << " " << __FILE__ << endl; VI par, ran; void init(int n){ par = VI(n); ran = VI(n, 0); REP(i, n){ par[i] = i; } } int find(int x){ if(par[x] == x){ return x; } return par[x] = find(par[x]); } void unite(int x, int y){ x = find(x); y = find(y); if(x == y) return; if(ran[x] < ran[y]){ par[x] = y; } else{ par[y] = x; if(ran[x] == ran[y]) ran[x]++; } } bool same(int x, int y){ return find(x) == find(y); } int main() { cin.tie(0); ios::sync_with_stdio(false); int N, M, Q; cin >> N >> M >> Q; set s; vector AB(M); REP(i, M){ int A, B; cin >> A >> B; AB[i] = MP(A, B); s.insert(MP(A, B)); } vector CD(Q); REP(i, Q){ int C, D; cin >> C >> D; CD[i] = MP(C, D); s.erase(MP(C,D)); } VI ans(N + 1, 0); VVI R(N + 1); init(N + 1); EACH(p, s){ unite(p.first, p.second); R[p.first].push_back(p.second); R[p.second].push_back(p.first); } FOR(i, 1, N + 1){ if(same(1, i)){ ans[i] = -1; } } for(int i = Q - 1; i >= 0; i--){ int x, y; x = CD[i].first; y = CD[i].second; unite(x, y); R[x].push_back(y); R[y].push_back(x); if((ans[x] == 0 && same(1, x)) || (ans[y] == 0 && same(1, y))){ queue que; que.push(x); que.push(y); while(!que.empty()){ int cur = que.front(); que.pop(); if(ans[cur] == 0){ ans[cur] = i + 1; EACH(r, R[cur]) if(ans[r] == 0) que.push(r); } } } } FOR(i, 2, N + 1){ cout << ans[i] << endl; } return 0; }