#include #define rep(i,n) for(int i=0;i<(n);i++) #define ALL(A) A.begin(), A.end() using namespace std; typedef long long ll; typedef pair P; const ll mod = (ll)1e9 + 7LL; ll dp[10005][2][2][3][8]; // dp[i桁目][N未満であることが確定しているか 0 -> していない 1 -> している][3 の付く数字か 0 -> そうでない 1 -> そう][mod 3 の値][mod 8 の値] ll solve (string s){ memset (dp, 0LL, sizeof(dp)); int n = s.length(); dp[0][0][0][0][0] = 1LL; for (int i = 0; i < n; ++i){ int D = (int)(s[i] - '0'); for (int j = 0; j < 2; ++j){ for (int k = 0; k < 2; ++k){ for (int l = 0; l < 3; ++l){ for (int m = 0; m < 8; ++m){ for (int d = 0; d < (j ? 10 : D + 1); ++d){ (dp[i + 1][j || d < D][k || d == 3][(10 * l + d) % 3][(10 * m + d) % 8] += dp[i][j][k][l][m]) % mod; } // end for } // end for } // end for } // end for } // end for } // end for ll res = 0LL; for (int j = 0; j < 2; ++j){ for (int k = 0;k < 2; ++k){ for (int l = 0; l < 3; ++l){ for (int m = 0; m < 8; ++m){ if ((k == 1 || l == 0) && (m != 0)) (res += dp[n][j][k][l][m]) % mod; } // end for } // end for } // end for } // end for return res; } string minus_one(string s){ reverse(ALL(s)); for (int i = 0; i < s.length(); ++i){ if (s[i] != '0'){ s[i] = (char)((int)(s[0] - '0') - 1 + '0'); break; }else{ s[i] = '9'; } // end if } // end for while (s.length() > 1 && s[s.length() - 1] == '0') s = s.substr(0, s.length() - 1); reverse(ALL(s)); return s; } int main(){ string A, B; cin >> A >> B; A = minus_one(A); ll res = (solve(B) - solve(A) + mod) % mod; cout << res << endl; return 0; }