#include #include #include #include using namespace std; typedef long double LD; int main(int argc, char *argv[]) { cout.precision(16); LD x; cin >> x; LD ans = 1.6449340668482264; for (int n = 10000000; n > 0; --n) { ans += 1 / ((x + n) * (x + n)); ans -= 1 / ((LD)n * n); } cout << ans << endl; return 0; }