-- 剰余演算の分配則より (Wiki調べ)
-- ab mod n = ((a mod n) (b mod n)) mod n

factMod 0 = 1
factMod x = factMod (x - 1) * x `mod` (10^9 + 7)

myMod a n = a `mod` n

main = do
    str <- getLine
    let x = read str :: Integer
    print $ myMod (factMod x) (10^9 + 7)