#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; #define rep(i,a,n) for(int i=a; i=n; i--) #define pb(a) push_back(a) #define fr first #define sc second #define INF 2000000000 #define int long long int #define X real() #define Y imag() #define EPS (1e-10) #define EQ(a,b) (abs((a) - (b)) < EPS) #define EQV(a,b) ( EQ((a).X, (b).X) && EQ((a).Y, (b).Y) ) #define LE(n, m) ((n) < (m) + EPS) #define LEQ(n, m) ((n) <= (m) + EPS) #define GE(n, m) ((n) + EPS > (m)) #define GEQ(n, m) ((n) + EPS >= (m)) typedef vector VI; typedef vector MAT; typedef pair pii; typedef long long ll; typedef complex P; typedef pair L; typedef pair C; int dy[]={0, 0, 1, -1}; int dx[]={1, -1, 0, 0}; int const MOD = 1000000007; namespace std { bool operator<(const P& a, const P& b) { return a.X != b.X ? a.X < b.X : a.Y < b.Y; } } vector primes(int n) { bool used[20010] = {}; vector ret; rep(i,2,n+1) { if(!used[i]) { ret.push_back(i); int d = i; while(d <= n) used[d] = true, d += i; } } return ret; } int dp[20010]; signed main() { int n; cin >> n; vector prm = primes(n); memset(dp, -1, sizeof(dp)); dp[0] = 0; rep(i,0,prm.size()) { // printf("debug: prime = %lld\n", prm[i]); repr(j,n,0) { if(j - prm[i] < 0 || dp[j-prm[i]] == -1) continue; dp[j] = max(dp[j], dp[j-prm[i]] + 1); } } cout << dp[n] << endl; return 0; }