#include using namespace std; using V = pair; V merge(const V &l, const V &r) { return {l.first + r.first, l.second + r.second}; } struct SegmentTree { const int n; const V unit_value = {0, 0}; vector val; SegmentTree(int _n) : n(1 << (33-__builtin_clz(_n-1))), val(n, unit_value) {} void update(int i, const V &v) { i += n / 2; val[i] = merge(val[i], v); while (i > 1) { i >>= 1; val[i] = merge(val[i * 2 + 0], val[i * 2 + 1]); } } V query(int l, int r) const { l = max(0, min(n / 2, l)) + n / 2; r = max(0, min(n / 2, r)) + n / 2; V ret = unit_value; for (; l < r; l >>= 1, r >>= 1) { if (l & 1) ret = merge(ret, val[l++]); if (r & 1) ret = merge(ret, val[--r]); } return ret; } }; int64_t solve(const int n, const int k, const vector &A) { if (k == 1) return 0; vector compressor(A); { sort(compressor.begin(), compressor.end()); compressor.erase(unique(compressor.begin(), compressor.end()), compressor.end()); } auto compress = [&compressor](int i) { return lower_bound(compressor.begin(), compressor.end(), i) - compressor.begin(); }; int m = compressor.size(); int num_medians = n - k + 1; vector medians(num_medians); { multiset S(&A[0], &A[k]); auto it = next(S.begin(), k / 2); for (int i = k; i <= n; i++) { medians[i - k] = *it; S.insert(A[i]); if (A[i] < *it) it--; if (A[i-k] <= *it) it++; S.erase(S.lower_bound(A[i-k])); } } SegmentTree seg(m); int64_t ans = 1e18; for (int i = 0; i < n; i++) { int a = A[i]; seg.update(compress(a), {1, a}); if (i >= k) { int c = A[i-k]; seg.update(compress(c), {-1, -c}); } if (i >= k - 1) { int64_t median = medians[i-k+1]; int median_c = compress(median); V lower = seg.query(0, median_c); V higher = seg.query(median_c, m); int64_t inc_cost = median * lower.first - lower.second; int64_t dec_cost = higher.second - median * higher.first; int64_t cand = inc_cost + dec_cost; ans = min(ans, cand); } } return ans; } int main() { cin.tie(nullptr); ios::sync_with_stdio(false); int n, k; cin >> n >> k; vector A(n); for (int i = 0; i < n; i++) cin >> A[i]; cout << solve(n, k, A) << endl; return 0; }