#include using namespace std; using ll = long long; #define rep(i,n) for(int (i)=0;(i)<(int)(n);++(i)) #define all(x) (x).begin(),(x).end() #define pb push_back #define fi first #define se second #define dbg(x) cout<<#x" = "<<((x))< ostream& operator<<(ostream& o, const pair &p){o<<"("< ostream& operator<<(ostream& o, const vector &v){o<<"[";for(T t:v){o< factorize(ll n) { map r; ll t = n; for(int i=2; i*i<=n; ++i) { while(t%i==0) { ++r[i]; t/=i; } } if(t>1) ++r[t]; return r; } ll mod_pow(ll x, ll n) { ll r = 1; while(n) { if(n&1) (r*=x)%=mod; (x*=x)%=mod; n>>=1; } return r; } int main() { int n,k; cin >>n >>k; vector> a(n); vector p; rep(i,n) { ll x; cin >>x; map m = factorize(x); a[i] = m; for(const auto &v:m) p.pb(v.fi); } sort(all(p)); p.erase(unique(all(p)),p.end()); ll ans = 1; for(ll i:p) { priority_queue pq; rep(j,n) { int val = 0; if(a[j].count(i)) val = a[j][i]; pq.push(val); } int ct = 0; rep(j,k) { ct += pq.top(); pq.pop(); } (ans*=mod_pow(i,ct))%=mod; } cout << ans << endl; return 0; }