# include # include # include # include # include # include # include # include # include # include # include # include # include # include # include #include #include #include #include #include using namespace std; typedef long long int ll; const int N = 1000000; const int mod = 1000000007; const int INF = 1 << 30; #define rep(i,n) for(int i=(ll)0;i<(ll)n;++i) #define ALL(x) x.begin(),x.end() #define pp pair #define fi first #define se second ll ppow(ll x, ll n) { ll ans = 1; while (n > 0) { if ((n & 1) == 1)ans = ans + x; x = x * x; n >>= 1; ans %= mod; } return ans; } string YN(bool b) { return(b ? "YES" : "NO"); } string yn(bool b) { return(b ? "Yes" : "No"); } ll enemy[100000][3],m[2010][2010];//mは+1000して使う int main(){ ll n, k,sum=0; cin >> n >> k; rep(i, n)cin >> enemy[i][0] >> enemy[i][1] >> enemy[i][2]; ll x, y, w, h, d; rep(i, k) { cin >> x >> y >> w >> h >> d; m[x + 1000][y + 1000] += d; m[x + 1000 + w + 1][y+1000] -= d; m[x + 1000][y + 1000 + h + 1] -= d; m[x + 1000 + w + 1][y + 1000 + h + 1] += d; } rep(j,2010)rep(i, 2010)if (i > 0)m[i][j] += m[i - 1][j]; rep(i, 2010)rep(j, 2010)if (j > 0)m[i][j] += m[i][j - 1]; rep(i, n) { sum += max((ll)0, enemy[i][2] - m[enemy[i][0] + 1000][enemy[i][1] + 1000]); } cout << sum << endl; return 0; }