#include <iostream>
using namespace std;
typedef long long LL;
bool has3(LL n){
	while (n>0){
		if (n%10==3){
			return true;
		}
		n/=10;
	}
	return false;
}
int main(int argc, char* argv[])
{
	LL A,B;
	cin>>A>>B;
	LL A1,B1;
	A1=(A*3)/3;
	B1=(B*3)/3;
	for (LL i=A;i<=B;i++){
		if (i%3==0 || has3(i)){
			cout<<i<<endl;
		}
	}
	return 0;
}