#include <iostream>
using namespace std;

typedef long long ll;
int main(){
	ll N;
	cin >> N;

	int cnt = 0;
	for(ll p=2;p*p<=N;p++){
		while(N % p == 0){
			++cnt;
			N /= p;
		}
	}
	if(N != 1)++cnt;

	--cnt;
	if(cnt >= 2){
		cout << "YES" << endl;
	} else {
		cout << "NO" << endl;
	}

	return 0;
}