#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #define REP(i,s,n) for(int i=(int)(s);i<(int)(n);i++) using namespace std; typedef long long int ll; typedef vector VI; typedef pair PI; const double EPS=1e-9; const ll err = 1LL << 60; typedef pair result; result p_int(string s, int v) { if (v >= s.length()) { return result(0, err); } ll q = 0; int len = 0; for (; v + len < s.length(); ++len) { char c = s[v + len]; if (('0' <= c && c <= '9') == false) { break; } q *= 10; q += c - '0'; } if (len >= 1) { return result(len, q); } return result(0, err); } result p_expr(const string &s, int v) { ll res; int pos = v; result r1 = p_int(s, v); if (r1.first == 0) { return result(0, err); } pos += r1.first; res = r1.second; while (pos < s.length()) { char op = s[pos]; switch (op) { case '+': case '-': break; default: return result(pos - v, res); } result sub = p_int(s, pos + 1); if (sub.first == 0) { return result(pos - v, res); } res = op == '+' ? res + sub.second : res - sub.second; pos += sub.first + 1; } return result(s.length() - v, res); } int main(void){ string s; cin >> s; int n = s.length(); ll m = -234567892345LL; REP(i, 0, n) { string t = s.substr(i, n) + s.substr(0, i); result r = p_expr(t, 0); if (r.first != n) { continue; } m = max(m, r.second); } cout << m << endl; }