#include #include #include #include #include #include #include #include #include #define MAX_N 100001 #define INF_INT 2147483647 #define INF_LL 9223372036854775807 #define REP(i,n) for(int i=0;i<(int)(n);i++) using namespace std; typedef long long int ll; typedef pair P; void init(int n); int find(int n); void unite(int x,int y); bool same(int x, int y); ll bpow(ll,ll,ll); typedef vector vec; typedef vector mat; mat mul(mat &A,mat &B); mat pow(mat A,ll n); int dx[4] = {1,0,0,-1}; int dy[4] = {0,1,-1,0}; bool cmp_P(const P &a,const P &b){ return a.second < b.second; } int main() { ll N,sin; cin >> N; sin = N / (10E8+1); vector > kaibun(12,vector(0)); vector kaib(0); for(int i=0;i<=9;i++){ kaibun[1].push_back(i); kaib.push_back(i); } for(int i=0;i<=9;i++){ kaibun[2].push_back(i*11); kaib.push_back(i*11); } for(int i=3;i<=11;i++){ for(int j=0;j>= 1; } return res; } const int MOD = 1000000007; mat mul(mat &A, mat &B){ mat C(A.size(),vec(B[0].size())); REP(i,A.size())REP(k,B.size())REP(j,B[0].size()){ C[i][j] = (C[i][j] + A[i][k] * B[k][j]) % MOD; } return C; } mat pow(mat A,ll n) { mat B(A.size(),vec(A.size())); REP(i,A.size()){ B[i][i] = 1; } while(n > 0){ if ( n & 1) B = mul(B,A); A = mul(A,A); n >>= 1; } return B; }