#include "bits/stdc++.h" using namespace std; typedef long long ll; typedef pair pii; typedef pair pll; const int INF = 1e9; const ll LINF = 1e18; template ostream& operator << (ostream& out,const pair& o){ out << "(" << o.first << "," << o.second << ")"; return out; } template ostream& operator << (ostream& out,const vector V){ for(int i = 0; i < V.size(); i++){ out << V[i]; if(i!=V.size()-1) out << " ";} return out; } template ostream& operator << (ostream& out,const vector > Mat){ for(int i = 0; i < Mat.size(); i++) { if(i != 0) out << endl; out << Mat[i];} return out; } template ostream& operator << (ostream& out,const map mp){ out << "{ "; for(auto it = mp.begin(); it != mp.end(); it++){ out << it->first << ":" << it->second; if(mp.size()-1 != distance(mp.begin(),it)) out << ", "; } out << " }"; return out; } /* 問題文============================================================ ================================================================= 解説============================================================= ================================================================ */ ll dp[11][101][10001]; tuple can_pay(int i,int j,int k,int D){ int t; t = min(i,D/1000); i -= t; D -= t*1000; t = min(j,D/100); j -= t; D -= t*100; t = min(k,D); k -= t; D -= t; if(D) return tuple{-1,-1,-1}; return tuple{i,j,k}; } ll solve(){ fill(**dp,**dp+11*101*10001,-1); ll res = 0; vector A(3),B(3),C(3); int Db,Dc; for(auto& in:A) cin >> in; cin >> Db; for(auto& in:B) cin >> in; cin >> Dc; for(auto& in:C) cin >> in; dp[A[0]][A[1]][A[2]] = 0; for(int kassa = 0; kassa < 100; kassa++){ for(int i = 10; i >= 0; i--){ for(int j = 100; j >= 0; j--){ for(int k = 10000; k >= 0; k--){ if(dp[i][j][k] == -1) continue; { int ni,nj,nk; tie(ni,nj,nk) = can_pay(i, j, k, Db); if(ni != -1){ dp[ni+B[0]][nj+B[1]][nk+B[2]] = max(dp[ni+B[0]][nj+B[1]][nk+B[2]],dp[i][j][k]+1); } } { int ni,nj,nk; tie(ni,nj,nk) = can_pay(i, j, k, Dc); if(ni != -1){ dp[ni+C[0]][nj+C[1]][nk+C[2]] = max(dp[ni+C[0]][nj+C[1]][nk+C[2]],dp[i][j][k]+1); } } } } } } for(int i = 10; i >= 0; i--){ for(int j = 100; j >= 0; j--){ for(int k = 10000; k >= 0; k--){ res = max(res,dp[i][j][k]); } } } return res; } int main(void) { cin.tie(0); ios_base::sync_with_stdio(false); cout << solve() << endl; return 0; }