#include #include #include #include #include #define _USE_MATH_DEFINES #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; #define FOR(i,m,n) for(int i=(m);i<(n);++i) #define REP(i,n) FOR(i,0,n) #define ALL(v) (v).begin(),(v).end() const int INF = 0x3f3f3f3f; const long long LINF = 0x3f3f3f3f3f3f3f3fLL; const double EPS = 1e-8; const int MOD = 1000000007; // 998244353; const int dy[] = {1, 0, -1, 0}, dx[] = {0, -1, 0, 1}; /*-------------------------------------------------*/ int main() { cin.tie(nullptr); ios::sync_with_stdio(false); // freopen("input.txt", "r", stdin); string s; cin >> s; reverse(ALL(s)); int n = s.length(), ans = 0, pos = s.find('1'); while (pos < n) { int nx = s.find('0', pos); if (nx == s.npos) nx = n; int len = nx - pos; if (len >= 2 || (nx + 1 < n && s[nx + 1] == '1' && nx + 2 < n && s[nx + 2] == '1')) { ++ans; FOR(i, pos, nx) s[i] = '0'; if (nx == n) { s += '1'; ++n; } else { s[nx] = '1'; } pos = nx; } else { ++ans; pos = nx; nx = s.find('1', pos); if (nx == s.npos) nx = n; pos = nx; } } cout << ans << '\n'; return 0; }