#include using namespace std; using ll = long long; const ll MOD = 1000000007; ll modpow(ll x, ll n, ll mod = MOD) { ll res = 1; while (n > 0) { if (n & 1) res = res * x % mod; x = x * x % mod; n >>= 1; } return res; } using vec = vector; using mat = vector; mat mul(mat& A, mat& B) { mat C(A.size(), vec(B[0].size(), 0)); for (int i = 0; i < A.size(); i++) { for (int k = 0; k < B.size(); k++) { for (int j = 0; j < B[0].size(); j++) { (C[i][j] += A[i][k] * B[k][j] % MOD) %= MOD; } } } return C; } mat pow(mat A, ll n) { mat B(A.size(), vec(A.size(), 0)); for (int i = 0; i < A.size(); i++) { B[i][i] = 1; } while (n > 0) { if (n & 1) B = mul(B, A); A = mul(A, A); n >>= 1; } return B; } int main() { cin.tie(nullptr); ios::sync_with_stdio(false); int n, w; ll K; cin >> n >> w >> K; vector a(n); for (int i = 0; i < n; ++i) { cin >> a[i]; } vector dp(2 * w + 1, 0); dp[0] = 1; for (int i = 0; i < 2 * w; ++i) { for (int j : a) { if (i + j > 2 * w) continue; (dp[i + j] += dp[i]) %= MOD; } } ll x = dp[w], y = (dp[2 * w] + MOD - x * x % MOD) % MOD; mat A(3, vec(3, 0)); A[0][1] = 1; A[1][2] = 1; A[2][1] = y; A[2][2] = x; mat B = {{1}, {dp[w]}, {dp[2 * w]}}; A = pow(A, K); B = mul(A, B); cout << B[0][0] << "\n"; // f[i] = f[i - 2] * y + f[i - 1] * x return 0; }