#include #define rep(i, a) rep2 (i, 0, a) #define rep2(i, a, b) for (int i = (a); i < (b); i++) #define repr(i, a) repr2 (i, 0, a) #define repr2(i, a, b) for (int i = (b) - 1; i >= (a); i--) #define asn(a, b, c) fill_n(&(b), sizeof(a) / sizeof(b), c) using namespace std; typedef long long ll; const ll inf = 1e9; const ll mod = 1e9 + 7; void matmul(ll A[2][2], ll B[2][2]) { ll a[2][2], b[2][2]; rep (i, 2) { rep (j, 2) { a[i][j] = A[i][j]; b[i][j] = B[i][j]; B[i][j] = 0; } } rep (i, 2) { rep (k, 2) { rep (j, 2) { (B[i][j] += a[i][k] * b[k][j]) %= mod; } } } } void matpow(ll A[2][2], ll b, ll res[2][2]) { rep (i, 2) rep (j, 2) res[i][j] = i == j; while (b) { if (b & 1) matmul(A, res); matmul(A, A); b >>= 1; } } ll modpow(ll a, ll b) { ll res = 1; while (b > 0) { if (b & 1) (res *= a) %= mod; (a *= a) %= mod; b >>= 1; } return res; } ll bigmodulo(string &s, ll m) { ll res = 0; for (char d : s) { res *= 10; res += d - '0'; res %= m; } return res; } ll bigmodpow(ll a, string &b) { if (a == 0) return 0; ll B = bigmodulo(b, mod - 1); return modpow(a, B); } int main() { int N; cin >> N; ll ans = 1; rep (i, N) { ll C; string D; cin >> C >> D; ll A[2][2] = {{1, 1}, {1, 0}}; ll An[2][2]; matpow(A, C, An); ll m = (An[0][0] + An[1][0]) % mod; ans *= bigmodpow(m, D); ans %= mod; } cout << ans << endl; return 0; }