#include #define rep(i, a) rep2 (i, 0, a) #define rep2(i, a, b) for (int i = (a); i < (b); i++) #define repr(i, a) repr2 (i, 0, a) #define repr2(i, a, b) for (int i = (b) - 1; i >= (a); i--) using namespace std; typedef long long ll; struct BIT { int size; vector bit; BIT(int size) : size(size), bit(size + 1) {} void add(int k, ll x) { k++; while (k <= size) { bit[k] += x; k += k & -k; } } ll sum(int k) { k++; ll res = 0; while (k > 0) { res += bit[k]; k -= k & -k; } return res; } }; ll modulo(ll a, ll mod) { a %= mod; a += mod; a %= mod; return a; } vector> mergeseg(vector> seg) { vector> es; int n = seg.size(); rep (i, n) { es.emplace_back(seg[i].first, i); es.emplace_back(seg[i].second, i + n); } sort(es.begin(), es.end()); int num = 0; int left = 0; vector> res; rep (i, es.size()) { if (es[i].second < n) { if (num == 0) { left = es[i].first; } num++; } else { num--; if (num == 0) { int right = es[i].first; res.emplace_back(left, right); } } } return res; } ll sum(int l1, int r1, int l2, int r2, BIT &bit, int N) { vector> seg; if (l1 <= r1) { seg.emplace_back(l1, r1); } else { seg.emplace_back(0, r1); seg.emplace_back(l1, N * 2 - 1); } if (l2 <= r2) { seg.emplace_back(l2, r2); } else { seg.emplace_back(0, r2); seg.emplace_back(l2, N * 2 - 1); } seg = mergeseg(seg); ll res = 0; rep (i, seg.size()) { res += bit.sum(seg[i].second) - bit.sum(seg[i].first - 1); } return res; } int main() { int N, Q; cin >> N >> Q; BIT left(N * 3), right(N * 3); rep (i, Q) { int t = i + 1; string x; int y, z; cin >> x >> y >> z; if (x[0] == 'R') { y = modulo(y - t, N * 2); right.add(y, z); } else if (x[0] == 'L') { y = modulo(y + t, N * 2); left.add(y, z); } else { z--; ll ans = 0; // right { int l1 = modulo(y - t, N * 2); int r1 = modulo(z - t, N * 2); int l2 = modulo((N * 2 - 1 - z) - t, N * 2); int r2 = modulo((N * 2 - 1 - y) - t, N * 2); ans += sum(l1, r1, l2, r2, right, N); } // left { int l1 = modulo(y + t, N * 2); int r1 = modulo(z + t, N * 2); int l2 = modulo((N * 2 - 1 - z) + t, N * 2); int r2 = modulo((N * 2 - 1 - y) + t, N * 2); ans += sum(l1, r1, l2, r2, left, N); } cout << ans << endl; } } return 0; }