#include #include #include #include #include #include #include #include #include #include #include #include #define rep(i,n) for(int i=0;i<(int)(n);++i) #define iter(a) __typeof(a.begin()) #define FOR(it,a) for(iter(a)it=a.begin();it!=a.end();++it) #define F first #define S second #define SZ(a) (int)((a).size()) #define sz(a) SZ(a) #define pb(a) push_back(a) #define mp(a,b) make_pair(a,b) #define ALL(a) (a).begin(),(a).end() using namespace std; typedef long long ll; typedef pair PI; typedef unsigned long long ull; #define PR(...) do{cerr << "line : " << __LINE__ << endl; pr(#__VA_ARGS__, __VA_ARGS__);}while(0); template void pr(const string& name, T t){ cerr << name << ": " << t << endl; } template void pr(const string& names, T t, Types ... rest) { auto comma_pos = names.find(','); cerr << names.substr(0, comma_pos) << ": " << t << ", "; auto next_name_pos = names.find_first_not_of(" \t\n", comma_pos + 1); pr(string(names, next_name_pos), rest ...); } template ostream& operator<< (ostream& o, const pair& v){return o << "(" << v.F << ", " << v.S << ")";} template ostream& operator<< (ostream& o, const vector& v){o << "{";rep(i,SZ(v)) o << (i?", ":"") << v[i];return o << "}";} #define endl '\n' string in[110]; int dx[] = {0,1,0,-1}; int dy[] = {-1,0,1,0}; int vis[110][110]; int main(int argc, char *argv[]) { ll n,m; cin >> n >> m; rep(i,n) cin >> in[i]; int fr = 0; rep(i,n)rep(j,m) fr += in[i][j]=='.'; int vcnt = 1; rep(i,n)rep(j,m){ if(in[i][j] == '#') continue; //bool fl = i==1 && j == 1; rep(k,4){ ++vcnt; int sdir = k; int cx = i + dx[sdir]; int cy = j + dy[sdir]; if(cx < 0 || cx >= n || cy < 0 || cy >= m || in[cx][cy] == '#') continue; int cfr = 0; do{ //if(fl) PR(cx,cy); ++cfr; vis[cx][cy] = vcnt; int nx = cx + dx[sdir]; int ny = cy + dy[sdir]; if(nx < 0 || nx >= n || ny < 0 || ny >= m || vis[nx][ny] == vcnt || in[nx][ny]=='#') ++sdir; sdir &= 3; nx = cx + dx[sdir]; ny = cy + dy[sdir]; if(nx < 0 || nx >= n || ny < 0 || ny >= m || vis[nx][ny] == vcnt || in[nx][ny]=='#') break; cx = nx; cy = ny; //PR(cx,cy,cfr); }while(cx != i || cy != j); //PR(cx,cy,cfr); if(cfr == fr-1 && cx == i && cy == j){ cout << "YES" << endl; return 0; } //return 0; } } cout << "NO" << endl; }