#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; typedef long long ll; const int INF = (1 << 30) - 1; const ll INFLL= (1LL << 61) - 1; const int MOD = 1000000007; #define ALL(a) (a).begin(),(a).end() #define rALL(a) (a).rbegin(),(a).rend() #define FOR(i,a,b) for(int i=(a);i<(b);++i) #define REP(i,n) FOR(i,0,n) struct matrix{ ll space[50][50]; matrix operator *(const matrix &another) const{ matrix ans; for(int i = 0; i < 50; i++){ for(int j = 0; j < 50; j++){ ans.space[i][j] = 0; for(int k = 0; k < 50; k++){ ans.space[i][j] += space[i][k] * another.space[k][j]; ans.space[i][j] %= MOD; } } } return ans; } }; const matrix A={{{1, 1, 1, 1}, {1, 0, 0, 0}, {0, 1, 0, 0}, {0, 0, 1, 0}}}; const matrix E={{{1, 0, 0, 0}, {0, 1, 0, 0}, {0, 0, 1, 0}, {0, 0, 0, 1}}}; matrix power(long exponent, matrix &A, matrix &E){ if(exponent % 2){ return power(exponent - 1, A, E) * A; }else if(exponent){ matrix root_ans = power(exponent / 2, A, E); return root_ans * root_ans; }else{ return E; } } int main(){ cin.tie(nullptr); ios::sync_with_stdio(false); ll M,K; cin>>M>>K; matrix A,E; REP(i,M){ REP(j,M){ E.space[i][j]=(i==j); } } REP(i,M){ REP(j,M){ ll tmp=0; // 足し算 REP(k,M){ tmp+=((i+k)%M==j); } // 掛け算 REP(k,M){ tmp+=((i*k)%M==j); } A.space[i][j]=tmp; } } cout<