#include #define rep(i,n) for(int i = 0; i < (n); ++i) #define drep(i,n) for(int i = (n)-1; i >= 0; --i) #define srep(i,s,t) for (int i = s; i < t; ++i) using namespace std; typedef long long int ll; typedef pair P; #define yn {puts("Yes");}else{puts("No");} struct edge{ int to;double cost; }; const double INF = 1001001001; const int MAX_N = 200005; const int MAX_V = 200005; vector G[MAX_V]; double d[MAX_V]; void dijkstra(int s){ // greater

を指定することでfirstが小さい順に取り出せるようにする priority_queue, greater

> que; fill(d, d+MAX_V, INF); d[s] = 0; que.push(P(0, s)); while(!que.empty()){ P p = que.top(); que.pop(); int v = p.second; for(int i=0; i d[v] + e.cost){ d[e.to] = d[v] + e.cost; que.push(P(d[e.to], e.to)); } } } } int main() { int n, m; cin >> n >> m; int s, g; cin >> s >> g; s--; g--; double x[n], y[n]; rep(i,n)cin >> x[i] >> y[i]; rep(i,m){ int from,to; double cost; cin >> from >> to; from--; to--; edge e1, e2; cost = sqrt((x[from]-x[to])*(x[from]-x[to])+(y[from]-y[to])*(y[from]-y[to])); e1.to = to; e1.cost = cost; e2.to = from; e2.cost = cost; G[from].push_back(e1); G[to].push_back(e2); } dijkstra(s); double ans = d[g]; cout << fixed << setprecision(10) << ans << endl; return 0; }