#include #define rep(i, a) for (int i = (int)0; i < (int)a; ++i) #define rrep(i, a) for (int i = (int)a - 1; i >= 0; --i) #define REP(i, a, b) for (int i = (int)a; i < (int)b; ++i) #define RREP(i, a, b) for (int i = (int)a - 1; i >= b; --i) #define pb push_back #define eb emplace_back #define all(x) x.begin(), x.end() #define rall(x) x.rbegin(), x.rend() using ll = long long; constexpr ll mod = 1e9 + 7; constexpr ll INF = 1LL << 60; template inline bool chmin(T &a, T b) { if (a > b) { a = b; return true; } return false; } template inline bool chmax(T &a, T b) { if (a < b) { a = b; return true; } return false; } ll gcd(ll n, ll m) { ll tmp; while (m != 0) { tmp = n % m; n = m; m = tmp; } return n; } ll lcm(ll n, ll m) { return abs(n) / gcd(n, m) * abs(m); //gl=xy } using namespace std; void solve() { int n, q; cin >> n >> q; vector a(n); vector b(q); rep(i, n) cin >> a[i]; rep(i, q) cin >> b[i]; const ll m = 998244353; vector> dp(5, vector(n + 1)); dp[0][0] = 1; rep(i, n) { rep(k,i+1){ dp[(i + 1)%2][k + 1] += dp[i%2][k]; dp[(i + 1)%2][k] += (dp[i%2][k] * (a[i] - 1) + m) % m; dp[(i + 1)%2][k] %= m; dp[(i + 1)%2][k + 1] %= m; dp[i % 2][k] = 0; } } rep(i, q) cout << dp[n%2][b[i]] << "\n"; } int main() { ios::sync_with_stdio(false); cin.tie(0); cout << fixed << setprecision(15); solve(); return 0; }