#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #define fi first #define se second #define rep(i,n) for(int i = 0; i < n; ++i) #define rrep(i,n) for(int i = 1; i <= n; ++i) #define drep(i,n) for(int i = n-1; i >= 0; --i) #define gep(i,g,j) for(int i = g.head[j]; i != -1; i = g.e[i].next) #define each(it,c) for(__typeof((c).begin()) it=(c).begin();it!=(c).end();it++) #define rng(a) a.begin(),a.end() #define maxs(x,y) x = max(x,y) #define mins(x,y) x = min(x,y) #define pb push_back #define sz(x) (int)(x).size() #define pcnt __builtin_popcount #define snuke srand((unsigned)clock()+(unsigned)time(NULL)); using namespace std; typedef long long int ll; typedef pair P; typedef vector vi; typedef vector vvi; inline int in() { int x; scanf("%d",&x); return x;} inline void priv(vi a) { rep(i,sz(a)) printf("%d%c",a[i],i==sz(a)-1?'\n':' ');} const int MX = 100005, INF = 1000010000; const int MY = 100005; const ll LINF = 1000000000000000000ll; const double eps = 1e-10; int n; int ax[MX]; map mp; // Segment tree (RMQ type) struct seg { vector d; int x2; seg(){} seg(int mx){ x2 = 1; while(x2 < mx) x2 <<= 1; d.resize(x2<<1,{{0,-10,-10},{0,-10,-10}}); } void add(int i, vi x){ for(i+=x2;i;i>>=1) { if (d[i][0][0] <= x[0]) { if (d[i][0][1] != x[1]) d[i][1] = d[i][0]; d[i][0] = x; } else if (d[i][1][0] < x[0] && d[i][1][1] != x[1]) { d[i][1] = x; } } } vi get(int a, int b, int x, int i=1, int l=0, int r=-10){ // cout<= b) return {0,-10,-10}; if (a < 0) return {0,-10,-10}; if (b > x2) return {0,-10,-10}; if (r == -10) r = x2; if(a <= l && r <= b) { if (d[i][0][1] != x) return d[i][0]; return d[i][1]; } int c = (l+r)>>1; vi res = {0,-10,-10}; if(a < c) res = max(res,get(a,b,x,i<<1,l,c)); if(c < b) res = max(res,get(a,b,x,i<<1|1,c,r)); return res; } }; // int solve() { seg dl(MY), dr(MY); rep(i,n) { int a = ax[i]; vi ml = dl.get(0,a,a); vi mr = dr.get(a+1,MY,a); vi nl = max(dl.get(0,ml[1],a),dl.get(ml[1]+1,a,a)); vi nr = max(dr.get(a+1,mr[1],a),dr.get(mr[1]+1,MY,a)); dl.add(a,{mr[0]+1,mr[2],a}); dr.add(a,{ml[0]+1,ml[2],a}); dl.add(a,{nr[0]+1,nr[2],a}); dr.add(a,{nl[0]+1,nl[2],a}); // cout<se = cnt++; rep(i,n) ax[i] = mp[ax[i]]; int ans = solve(); if (ans < 3) ans = 0; cout<