#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #define all(a) a.begin(),a.end() #define rep(i, n) for (ll i = 0; i < (n); i++) #define pb push_back #pragma GCC optimize("O3") #pragma GCC optimize("unroll-loops") using namespace std; typedef long long ll; typedef unsigned long long ull; typedef long double ld; typedef pair P; typedef complex com; constexpr int inf = 1000000010; constexpr ll INF = 1000000000000000010; constexpr ld eps = 1e-12; constexpr ld pi = 3.141592653589793238; template inline bool chmax(T &a, const U &b) { if (a < b) { a = b; return true; } return false; } template inline bool chmin(T &a, const U &b) { if (a > b) { a = b; return true; } return false; } signed main() { cin.tie(0); ios::sync_with_stdio(false); cout << fixed << setprecision(20); int n; cin >> n; vector a(n); rep(i, n) cin >> a[i]; vector vis(n, -1); vector num; ll now = 0; ll per = 0, pl = 0; while (true) { if (vis[now % n] != -1) { per = num.size() - vis[now % n]; pl = now - num[vis[now % n]]; break; } vis[now % n] = num.size(); num.pb(now); now += a[now % n]; } ll bor = num.size() - 1; int q; cin >> q; while (q--) { ll k; cin >> k; if (k <= bor) cout << num[k] << '\n'; else { ll dif = (k - bor - 1) / per + 1; cout << dif * pl + num[k - dif * per] << '\n'; } } }