#include #define rep(i,n) for(int i = 0; i < (n); ++i) #define srep(i,s,t) for (int i = s; i < t; ++i) #define drep(i,n) for(int i = (n)-1; i >= 0; --i) using namespace std; typedef long long int ll; typedef pair P; #define yn {puts("YES");}else{puts("NO");} #define MAX_N 200005 int dx[4] = {-1, 0, 1, 0}; int dy[4] = {0, -1, 0, 1}; int main() { int h, w; cin >> h >> w; int sx, sy, gx, gy; cin >> sx >> sy >> gx >> gy; sx++; sy++; gx++; gy++; string s[h]; rep(i,h) cin >> s[i]; int a[h+4][w+4]; rep(i,h+4){ rep(j,w+4){ a[i][j] = 100; } } rep(i,h){ rep(j,w){ a[i+2][j+2] = s[i][j] - '0'; } } queue

que; int f[h+4][w+4]; rep(i,h+4){ rep(j,w+4){ f[i][j] = 0; } } que.push(P(sx,sy)); while(que.size() > 0){ int x = que.front().first; int y = que.front().second; que.pop(); rep(i,4){ int nx = x + dx[i]; int ny = y + dy[i]; if(abs(a[x][y]-a[nx][ny]) <= 1 && f[nx][ny] == 0){ f[nx][ny] = 1; que.push(P(nx,ny)); } nx = x + dx[i]*2; ny = y + dy[i]*2; if(a[x][y]==a[nx][ny]&&a[(x+nx)/2][(y+ny)/2]