#include <bits/stdc++.h>
using namespace std;

// #define int long long
#define rep(i, n) for (long long i = (long long)(0); i < (long long)(n); ++i)
#define reps(i, n) for (long long i = (long long)(1); i <= (long long)(n); ++i)
#define rrep(i, n) for (long long i = ((long long)(n)-1); i >= 0; i--)
#define rreps(i, n) for (long long i = ((long long)(n)); i > 0; i--)
#define irep(i, m, n) for (long long i = (long long)(m); i < (long long)(n); ++i)
#define ireps(i, m, n) for (long long i = (long long)(m); i <= (long long)(n); ++i)
#define irreps(i, m, n) for (long long i = ((long long)(n)-1); i > (long long)(m); ++i)
#define SORT(v, n) sort(v, v + n);
#define REVERSE(v, n) reverse(v, v+n);
#define vsort(v) sort(v.begin(), v.end());
#define all(v) v.begin(), v.end()
#define mp(n, m) make_pair(n, m);
#define cinline(n) getline(cin,n);
#define replace_all(s, b, a) replace(s.begin(),s.end(), b, a);
#define PI (acos(-1))
#define FILL(v, n, x) fill(v, v + n, x);
#define sz(x) (long long)(x.size())

using ll = long long;
using vi = vector<int>;
using vvi = vector<vi>;
using vll = vector<ll>;
using vvll = vector<vll>;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
using vs = vector<string>;
using vpll = vector<pair<ll, ll>>;
using vtp = vector<tuple<ll,ll,ll>>;
using vb = vector<bool>;

template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }

template<class t> using vc=vector<t>;
template<class t> using vvc=vc<vc<t>>;

const ll INF = 1e9+10;
const ll MOD = 1e9+7;
const ll LINF = 1e18;

// 求めたいのは確率でなく期待値
// dp[i]:=iを作るために必要な回数の期待値
// xから始めて0にするまでの期待値

double dp[1001001];

double S[7];

double rec(ll v){
  if(v<=0) return 0;
  if(dp[v]) return dp[v];
  
  reps(i,6){
    dp[v]+=(rec(v-i)+1)*S[i];
  }
  return dp[v];
}

signed main()
{
  cin.tie( 0 ); ios::sync_with_stdio( false );
  
  S[1]=1.0/12;
	S[2]=2.0/12;
	S[3]=3.0/12;
	S[4]=1.0/12;
	S[5]=3.0/12;
	S[6]=2.0/12;
  
  ll t; cin>>t;
  vll x(t);
  rep(i,t) cin>>x[i];
  
  rep(i,t){
    printf("%.15lf\n", rec(x[i]));
  }
  
}