def main(n,m,p,a): ma0=max(a) if ma0>m:return 1 b=[1]*n for i in range(n): while a[i]%p==0: a[i]//=p b[i]+=1 ma1=max(a) if ma1==1: print(-1) exit() ary=[0]*50 for i in range(n): ary[b[i]]=max(ary[b[i]],a[i]) ary=[[i,v] for i,v in enumerate(ary) if v!=0] from heapq import heappush,heappop todo=[[0,1]] inf=float('inf') seen=[0]*1000 seen[0]=1 # seen[i]:操作回数i回における最大 while todo: i,v=heappop(todo) if v*ma0>m:return i+1 for di,dv in ary: if i+di<1000 and seen[i+di]