#include <iostream>
#include <cstdio>
#include <array>
#include <vector>
#include <algorithm>
#define repeat(i,n) for (int i = 0; (i) < (n); ++(i))
#define repeat_from(i,m,n) for (int i = (m); (i) < (n); ++(i))
#define repeat_reverse(i,n) for (int i = (n)-1; (i) >= 0; --(i))
using namespace std;
double por(double p, double q) { // probability or
    return 1 - (1-p)*(1-q);
}
inline bool at(int s, int i) {
    return s & (1 << i);
}
int main() {
    int h, w; cin >> h >> w;
    vector<vector<double> > p(h, vector<double>(w)); repeat (y,h) repeat (x,w) { cin >> p[y][x]; p[y][x] /= 100; }
    vector<vector<int   > > s(h, vector<int   >(w)); repeat (y,h) repeat (x,w)   cin >> s[y][x];
    vector<vector<double> > dp(h+1, vector<double>(1<<w)); // dp[y][hand] = probability
    dp[0][0] = 1;
    repeat (y,h) {
        repeat (knowledge,1<<w) {
            double q = 1;
            repeat (x,w) q *= at(knowledge,x) ? p[y][x] : 1 - p[y][x];
            repeat (phand,1<<w) {
                int hand = 0;
                repeat (x,w) {
                    if (s[y][x] == 0 and at(knowledge,x)) hand |= (1<<x);
                    if (s[y][x] == 1 and at(knowledge,x) and at(phand,x)) hand |= (1<<x);
                }
                repeat_from (x,1,w) {
                    if (s[y][x] == 1 and at(knowledge,x) and at(hand,x-1)) hand |= (1<<x);
                    if (s[y][x] == 2 and at(knowledge,x) and at(hand,x-1) and at(phand,x)) hand |= (1<<x);
                }
                repeat_reverse (x,w-1) {
                    if (s[y][x] == 1 and at(knowledge,x) and at(hand,x+1)) hand |= (1<<x);
                    if (s[y][x] == 2 and at(knowledge,x) and at(hand,x+1) and at(phand,x)) hand |= (1<<x);
                }
                repeat_from (x,1,w-1) {
                    if (s[y][x] == 2 and at(knowledge,x) and at(hand,x-1) and at(hand,x+1)) hand |= (1<<x);
                    if (s[y][x] == 3 and at(knowledge,x) and at(hand,x-1) and at(hand,x+1) and at(phand,x)) hand |= (1<<x);
                }
                dp[y+1][hand] += q * dp[y][phand];
            }
        }
    }
    double result = 0;
    repeat (y,h) repeat (row,1<<w) {
        result += __builtin_popcount(row) * dp[y+1][row];
    }
    printf("%.12lf\n", result);
    return 0;
}