//yukicoder 253 "ややこしい鶴亀算"
#include <bits/stdc++.h>
using namespace std;

int main() {
	int n, a, sum = 0;
	cin >> n;
	for (int i = 0; i < n; i++) {
		cin >> a;
		sum += a;
	}
	int ans = (sum + 2 * n - 2 * n * n) / (2 * n - 2);
	cout << n - ans << " " << ans << endl; 
	return 0;
}