#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #pragma warning(disable:4996) //#define ATCODER #ifdef ATCODER #include #endif typedef long long ll; typedef unsigned long long ull; #define LINF 9223300000000000000 #define LINF2 1223300000000000000 #define LINF3 1000000000000 #define INF 2140000000 const long long MOD = 1000000007; //const long long MOD = 998244353; using namespace std; #ifdef ATCODER using namespace atcoder; #endif vector>> g; // to,edge vector c; vector num0; ll ans0; int dfs(int par, int curr, ll dd) { int sum = 0; for (int i = 0; i < (int)g[curr].size(); i++) { int ne=g[curr][i].first; int edge = g[curr][i].second; if (par == ne) continue; num0[edge] = dfs(curr, ne, dd+c[edge]); sum += num0[edge]; } if (sum == 0) { ans0 += dd; sum++; } return sum; } void solve() { int n, K; scanf("%d%d", &n, &K); c.resize(n - 1); g.resize(n); num0.resize(n - 1); for (int i = 0; i < n - 1; i++) { int a, b; scanf("%d%d%d", &a, &b, &c[i]); a--; b--; g[a].push_back(make_pair(b, i)); g[b].push_back(make_pair(a, i)); } int ret = dfs(-1, 0, 0); //assert(ret == n); vector> dp(n, vector(K + 1, -LINF)); dp[0][0] = 0; for (int i = 0; i < n - 1; i++) { for (int j = 0; j <= K; j++) { if (dp[i][j] < 0) continue; dp[i + 1][j] = max(dp[i + 1][j], dp[i][j]); int j2 = j + c[i]; if (j2 <= K) { dp[i + 1][j2] = max(dp[i + 1][j2], dp[i][j] + (ll)c[i]*num0[i]); } } } ll ans = -LINF; for (int j = 0; j <= K; j++) { ans=max(ans, dp[n - 1][j]); } printf("%lld\n", ans+ans0); return; } int main() { #if 1 solve(); #else int T, t; scanf("%d", &T); for (t = 0; t < T; t++) { //printf("Case #%d: ", t + 1); solve(); } #endif return 0; }