#include #include #include #include //#include #include #include #include #include #include //#include #include #include #include //#include #include #include //#include #include #include #include #include const int dx[] = {1, 0, -1, 0}; const int dy[] = {0, 1, 0, -1}; using namespace std; typedef long long ll; typedef vector vi; typedef vector vll; typedef pair pii; const int MAXN = 3003; const int INF = 1e9; int dp1[MAXN][MAXN][2]; int dp2[MAXN][MAXN][2]; int w[MAXN]; int n, m; int dfs1(int now, int rest, int pre) { if (now == n) { if (rest > 0) return -INF/2; if (pre) return w[n-1]; else return 0; } int& ret = dp1[now][rest][pre]; if (ret > -INF) return ret; ret = dfs1(now+1, rest, 0); if (rest > 0) { int tmp = dfs1(now+1, rest-1, 1); if (pre) tmp += w[now-1]; ret = max(ret, tmp); } return ret; } int dfs2(int now, int rest, int pre) { if (now==n) { if (rest > 0) return -INF/2; return 0; } int& ret = dp2[now][rest][pre]; if (ret > -INF) return ret; ret = dfs2(now+1, rest, 0); if (rest > 0) { int tmp = dfs2(now+1, rest-1, 1); if (pre) tmp += w[now-1]; ret = max(ret, tmp); } return ret; } int main() { cin.tie(0); ios::sync_with_stdio(false); cin >> n >> m; for (int i = 0; i < n; i++) cin >> w[i]; for (int i = 0; i <= n; i++) { for (int j = 0; j <= n; j++) { for (int k = 0; k < 2; k++) dp1[i][j][k] = dp2[i][j][k] = -INF; } } // 最初の頂点を入れる int ans = dfs1(1, m-1, 1); ans = max(ans, dfs2(1, m, 0)); cout << ans << endl; return 0; }