#a, b, cがすべて異なるとき: 3つの集合の和集合
#n(AorBorC) = n(A)+n(B)+n(C)-n(A&B)-n(B&C)-n(C&A)+n(A&B&C)
#a, b, cのうちちょうど2つが等しいとき: 2つの集合の和集合
#a, b, cのどれもが等しいとき: n(a)

N = input()
li = map(int, raw_input().split())
li_uniq = []    #重複を消す
for i in li:
    if not i in li_uniq:
        li_uniq.append(i)

if len(li_uniq) == 3:
    a = li_uniq[0]
    b = li_uniq[1]
    c = li_uniq[2]
    na = N/a
    nb = N/b
    nc = N/c
    nab = N/(a*b)
    nbc = N/(b*c)
    nca = N/(c*a)
    nabc = N/(a*b*c)
    print na+nb+nc-nab-nbc-nca+nabc
elif len(li_uniq) == 2:
    a = li_uniq[0]
    b = li_uniq[1]
    na = N/a
    nb = N/b
    nab = N/(a*b)
    print na+nb-nab
else:
    a = li_uniq[0]
    na = N/a
    print na