#include<cstdio>
#include<cstring>
#include<cctype>
#include<cmath>
#include<climits>
#include<algorithm>
#include<vector>
#include<valarray>
#include<string>
#include<set>
#include<map>
#include<stack>
#include<queue>
#include<iostream>
#include<iomanip>
using namespace std;
   
   
#define rep(i,n) for(int i=0;i<n;i++)
#define REP(i,n) for(int i=1;i<=n;i++)
#define drep(i,n) for(int i=n-1;i>=0;i--)
#define DREP(i,n) for(int i=n;i>0;i--)
#define Rep(i,m,n) for(int i=m;i<n;i++)
#define ReP(i,m,n) for(int i=m;i<=n;i++)
#define scani(a) scanf("%d",&a)
#define scand(a) scanf("%lf",&a)
#define scans(s) scanf("%s",s)
#define readi(a) int a;scanf("%d",&a)
#define printi(a) printf("%d",a)
#define prints(s) printf("%s",s)
#define even(n) (((n)+1)%2)
#define odd(n) ((n)%2)
#define sg(x) ((x)?1:0)
#define LF printf("\n")
#define SPACE printf(" ")
#define pb push_back
#define mp make_pair
#define bs binary_search
#define all(a) (a).begin(),(a).end()
#define forall(itr,a) for(auto itr=(a).begin();itr!=(a).end();++itr)
   
typedef long long LL;
typedef vector<int> vi;
typedef vector<vector<int>> vvi;
typedef pair<double,double> pdd;
typedef pair<int,int> pii;
   
const double pi = acos(-1.0);
double rad(double t){return t*pi/180.0;}
double deg(double d){return d*180.0/pi;}
template<typename T>T GCD(T x,T y){return y?GCD(y,x%y):x;}
template<typename T>T LCM(T x,T y){return x/GCD(x,y)*y;}
template<class T>ostream& operator<<(ostream& os,const set<T>& s){os<<"{";for(auto itr=s.begin();s.end() != itr;++itr){if(itr!=s.begin())os<<',';os<<*itr;}os<<"}";return os;}
template<class S,class T>ostream& operator<<(ostream& os,const pair<S,T>& p){os<<'('<<p.first<<','<<p.second<<')';return os;}
const int MOD = (int)pow(10,9) +7;

int count(int k){
  int ret=0;
  rep(i,sizeof(int)*8){
    ret += 1 & (k >> i);
  }
  return ret;
}

int solve(int n){
  int infty=n+1;
  vi masu(infty,n+1);
  queue<int> q;
  q.push(1);
  masu[1]=1;
  while(!q.empty()){
    int pos = q.front();
    q.pop();
    int n1=pos+count(pos);
    int n2=pos-count(pos);
    if(n1<=n&&masu[n1]==infty){
      masu[n1] = masu[pos] + 1;
      q.push(n1);
    }
    if(n2>=1&&masu[n2]==infty){
      masu[n2] = masu[pos] + 1;
      q.push(n2);
    }
    if(masu[n]!=infty)return masu[n];
  }
  return -1;
}

int main(){
  int n;
  cin >> n;
  cout << solve(n) << endl;
  return 0;
}