XY = Struct.new(:x, :y)

def draw_square(xy1, xy2)
  ret = []

  w = xy2.x - xy1.x
  h = xy2.y - xy1.y

  if w != 0 || h != 0 then
    xy3 = XY.new(xy2.x + h, xy2.y - w)
    xy4 = XY.new(xy3.x - w, xy3.y - h)
    ret << [xy3, xy4]

    xy3 = XY.new(xy2.x - h, xy2.y + w)
    xy4 = XY.new(xy3.x - w, xy3.y - h)
    ret << [xy3, xy4]
  end

  return ret
end

xy1, xy2, xy3 = gets.split.map(&:to_i).each_slice(2).map{|x,y| XY.new(x, y)}

#2点を使って、正方形を描くのに必要な他の2点を列挙する。
#列挙された2点の片方が3点目であれば、もう片方の点が答え。

ans = nil
draw_square(xy1, xy2).each do |xy34|
  ans = xy34[1] if xy34[0] == xy3
  ans = xy34[0] if xy34[1] == xy3
end
draw_square(xy1, xy3).each do |xy34|
  ans = xy34[1] if xy34[0] == xy2
  ans = xy34[0] if xy34[1] == xy2
end

puts ans ? "#{ans.x} #{ans.y}" : -1