#include #include #include #include #include #include #include #include #include #include #include #include #define rep(i,n) for(int i=0;i<(int)(n);++i) #define iter(a) __typeof(a.begin()) #define FOR(it,a) for(iter(a)it=a.begin();it!=a.end();++it) #define F first #define S second #define SZ(a) (int)((a).size()) #define sz(a) SZ(a) #define pb(a) push_back(a) #define mp(a,b) make_pair(a,b) #define ALL(a) (a).begin(),(a).end() using namespace std; typedef long long ll; typedef pair PI; typedef unsigned long long ull; #define PR(...) do{cerr << "line : " << __LINE__ << endl; pr(#__VA_ARGS__, __VA_ARGS__);}while(0); template void pr(const string& name, T t){ cerr << name << ": " << t << endl; } template void pr(const string& names, T t, Types ... rest) { auto comma_pos = names.find(','); cerr << names.substr(0, comma_pos) << ": " << t << ", "; auto next_name_pos = names.find_first_not_of(" \t\n", comma_pos + 1); pr(string(names, next_name_pos), rest ...); } template ostream& operator<< (ostream& o, const pair& v){return o << "(" << v.F << ", " << v.S << ")";} template ostream& operator<< (ostream& o, const vector& v){o << "{";rep(i,SZ(v)) o << (i?", ":"") << v[i];return o << "}";} const int dx[] = {0,1,0,-1}; const int dy[] = {-1,0,1,0}; #define endl '\n' int n,d,k; int ans[100]; bool vis[110][1100][11]; void rec(int ne,int co,int ck){ if(co == 0 && ck == k){ rep(i,k){ if(i) cout << ' '; cout << ans[i]; } cout << endl; exit(0); } if(ck >= k) return; if(co <= 0 || ne == n+1) return; if(vis[ne][co][ck]) return; vis[ne][co][ck] = true; ans[ck] = ne; rec(ne+1,co-ne,ck+1); rec(ne+1,co,ck); } int main(int argc, char *argv[]) { cin >> n >> d >> k; rec(1,d,0); cout << -1 << endl; return 0; }