#include #include #include #include #include #include #include using namespace std; #define FOR(i,a,b) for (int i=(a);i<(b);i++) #define FORR(i,a,b) for (int i=(b)-1;i>=(a);i--) #define REP(i,n) for (int i=0;i<(n);i++) #define RREP(i,n) for (int i=(n)-1;i>=0;i--) #define pb push_back #define ALL(a) (a).begin(),(a).end() #define EPS (1e-10) #define EQ(a,b) (abs((a)-(b)) < EPS) #define PI 3.1415926535 typedef long long ll; typedef pair P; //typedef complex C; const int INF = 99999999; const int MAX_N = 100; const int MAX_C = 100000; int C, N; int a[MAX_N]; // dp[i][j] = i番目までの和がjとなるようなsum(x)(i=0..i)の最小値(存在しなければ-1) int dp[MAX_N][MAX_C + 1]; void input() { cin >> C >> N; REP(i, N) cin >> a[i]; } void solve() { REP(i, N) REP(j, C + 1) dp[i][j] = INF; // x0について int t_sum = 0; int x0 = 0; while (t_sum <= C) { dp[0][t_sum] = x0; t_sum += a[0]; x0++; } // 配るDP REP(i, N - 1) { REP(j, C + 1) { if (dp[i][j] != INF) { int nxt_sum = j; int nxt_x = 0; while (nxt_sum <= C) { dp[i + 1][nxt_sum] = min(dp[i + 1][nxt_sum], dp[i][j] + nxt_x); nxt_sum += a[i + 1]; nxt_x++; } } } } if (dp[N - 1][C] != INF) { cout << dp[N - 1][C] << endl; } else { cout << -1 << endl; } } int main() { input(); solve(); }