#define _CRT_SECURE_NO_WARNINGS
#include <iostream>
#include <cstdio>
#include <cstring>
#include <ctime>
#include <string>
#include <vector>
#include <algorithm>
#include <cmath>
#include <sstream>
#include <utility>
using namespace std;
typedef long long ll;
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef pair<int,int> pii;
#define all(c) (c).begin(), (c).end()
#define loop(i,a,b) for(ll i=a; i<ll(b); i++)
#define rep(i,b) loop(i,0,b)
#define each(e,c) for(auto&e:c)
#define pb push_back
#define eb emplace_back
#define mp make_pair
#define mt make_tuple
#define lb lower_bound
#define ub upper_bound
#ifdef DEBUG
#define dump(...) (cerr<<#__VA_ARGS__<<" = "<<(DUMP(),__VA_ARGS__).str()<<" ["<<__LINE__<<"]"<<endl)
struct DUMP:ostringstream{template<class T>DUMP &operator,(const T&t){if(this->tellp())*this<<", ";*this<<t;return *this;}};
#else
#define dump(...)
#endif

// ちょうどK個
// 価値の和がD個

// iまでで個数jで和をkにできるか？
bool dp[111][111][1111];
tuple<int,int,int> src[111][111][1111];

int N,D,K;
int main(){
    while(cin>>N>>D>>K && N){
        dump(N,D,K);
        memset(dp,0,sizeof(dp));
        dp[0][0][0] = true;
        for(int i=0;i<N;i++){
            for(int j=K;j>=0;j--){
                for(int k=D;k>=0;k--){
                    if(dp[i][j][k]){
                        dp[i+1][j+1][k+i+1] = true;
                        src[i+1][j+1][k+i+1] = tie(i,j,k);
                    }
                    if(dp[i][j][k]){
                        dp[i+1][j][k] = true;
                        src[i+1][j][k] = tie(i,j,k);
                    }
                }
            }
        }
        vi diff;
        int n,k,d;
        tie(n,k,d) = tie(N,K,D);
        while(tie(n,k,d)!=mt(0,0,0)){
            tie(n,k,d) = src[n][k][d];
            if(diff.size()==0 || diff.back()!=d) diff.push_back(d);
        }
        int t = 0;
        if(dp[N][K][D]){
            int n = diff.size();
            vi ans;
            rep(i,n-1){
                int u = diff[n-i-2] - diff[n-i-1];
                ans.push_back(u);
                t += u;
            }
            if(t!=D){
                ans.push_back(D-t);
            }
            rep(i,ans.size()){
                cout << ans[i] << (i!=ans.size()-1 ? " " : "\n");
            }
        }else{
            puts("-1");
        }
    }
}