n = int(input())
a = list(map(int,input().split()))

#dp[i][j] = i番目まで，jを作る場合の数

dp = [[0]*(pow(2,15)+1) for i in range(n)]

dp[0][0] = 1
dp[0][a[0]] = 1

for i in range(1,n):
    for j in range(pow(2,14)+1):
        dp[i][j] = dp[i-1][j] + dp[i-1][j^a[i]]
ans = 0
for i in range(pow(2,15)+1):
    if dp[-1][i] > 0:
        ans += 1
print(ans)