#include <iostream>
#include <vector>
#include <cstdio>
#include <sstream>
#include <map>
#include <string>
#include <algorithm>
#include <queue>
#include <cmath>

using namespace std;

typedef struct{
	int to;
	int cost;
}edge;


//distance from s
//O(E log V)
void dijkstra(vector<vector<edge> > &G, vector<int> &dist, int s){

	//INF as distance
	const int INF = 10000000;
	
	//first : distance from s, second : its vertex
	priority_queue< pair<int,int> , vector<pair<int,int> >, greater< pair<int,int> > > pq;
	 
	fill(dist.begin(), dist.end(), INF);
	dist[s] = 0;
	pq.push( make_pair(dist[s], s) );
	while(!pq.empty()){
		pair<int,int> q = pq.top();
		pq.pop();
		int from = q.second;
		if(dist[from] < q.first) continue; // it's not minimum distance
		int n=G[from].size();
		for(int i=0; i<n; i++){
			edge e = G[from][i];
			if(dist[e.to] > dist[from] + e.cost){
				dist[e.to] = dist[from] + e.cost;
				pq.push( make_pair(dist[e.to], e.to) );
			}
		}
	}
}
 
void add_edge(vector<vector<edge> > &G, int from, int to, int cost){
	G[from].push_back( (edge){to, cost} );
	//G[to].push_back( (edge){from, cost} );
}


bool is_kadomatsu_sec(int a, int b, int c){
	if(a==b || b==c || c==a) return false;
	if(b<a && b<c) return true;
	if(b>a && b>c) return true;
	return false;
}

int x[] = {0,1,0,-1};
int y[] = {-1,0,1,0};

int main(){
	int w,h;
	cin >> w >> h;
	vector<vector<int> > v(h, vector<int>(w));
	for(int i=0; i<h; i++){
		for(int j=0; j<w; j++){
			cin >> v[i][j];
		}
	}

	vector<vector<edge> > G(w*h*4);
	for(int i=0; i<h; i++){
		for(int j=0; j<w; j++){
			
			for(int k=0; k<4; k++){
				int xx = j+x[k];
				int yy = i+y[k];
				if(xx<0 || xx>=w) continue;
				if(yy<0 || yy>=h) continue;

				for(int l=0; l<4; l++){
					if(l==k) continue;
					int xxx = j+x[l];
					int yyy = i+y[l];
					if(xxx<0 || xxx>=w) continue;
					if(yyy<0 || yyy>=h) continue;

					if(is_kadomatsu_sec(v[yy][xx], v[i][j], v[yyy][xxx])){
						add_edge(G, i*w+j + w*h*k, yyy*w+xxx + w*h*((l+2)%4), 1);
					}
				}
				
			}
			
		}
	}

	const int INF = 10000000;

	int ans = INF;

	vector<int> dist(w*h*4);
	
	for(int i=0; i<4; i++){
		int x1 = 0+x[i];
		int y1 = 0+y[i];
		if(x1<0 || x1>=w) continue;
		if(y1<0 || y1>=h) continue;
		
		for(int j=0; j<4; j++){
			int x2 = x1+x[j];
			int y2 = y1+y[j];
			if(x2<0 || x2>=w) continue;
			if(y2<0 || y2>=h) continue;
			if(x2==0 && y2==0) continue;
			
			
			if(is_kadomatsu_sec(v[0][0], v[y1][x1], v[y2][x2])){
				
				dijkstra(G, dist, y2*w+x2 + w*h*((j+2)%4));
				for(int k=0; k<4; k++){
					ans = min(ans, dist[ (h-1)*w+(w-1) + w*h*k ]+2);
				}
			}
			
		}
	}

	if(ans < INF) cout << ans << endl;
	else cout << -1 << endl;
	return 0;
}