#line 1 "yukicoder-0117.test.cpp" #define PROBLEM "https://yukicoder.me/problems/no/117" #line 1 "/home/sakflat/CP/_library/cpp/template/template.cpp" //yukicoder@cpp17 #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; using ll = long long; using P = pair; const ll MOD = 998244353; const ll MODx = 1000000007; const int INF = (1<<30)-1; const ll LINF = (1LL<<62LL)-1; const double EPS = (1e-10); P ar4[4] = {{0,1},{0,-1},{1,0},{-1,0}}; P ar8[8] = {{-1,-1},{-1,0},{-1,1},{0,-1},{0,1},{1,-1},{1,0},{1,1}}; template vector make_vector(size_t a, T b) { return vector(a, b); } template auto make_vector(size_t a, Ts... ts) { return vector(a, make_vector(ts...)); } /* 確認ポイント cout << fixed << setprecision(n) << 小数計算//n桁の小数表記になる 計算量は変わらないが楽できるシリーズ min(max)_element(iter,iter)で一番小さい(大きい)値のポインタが帰ってくる count(iter,iter,int)でintがiterからiterの間にいくつあったかを取得できる */ /* function corner below */ /* Function corner above */ /* comment outed because can cause bugs __attribute__((constructor)) void initial() { cin.tie(0); ios::sync_with_stdio(false); } */ #line 1 "/home/sakflat/CP/_library/cpp/math/combination.cpp" template struct Combination { long long n_max; vector fac, inv, finv; Combination(int n):n_max(n), fac(n+1,1), inv(n+1,1), finv(n+1,1){ for(int i = 2; n > i; i++){ fac[i] = (fac[i-1]*i)%mod; inv[i] = mod-((inv[mod%i]*(mod/i))%mod); finv[i] = (finv[i-1]*inv[i])%mod; } } long long C(int n, int r){ if(n < r)return 0; if(n > n_max)return 0; return (((fac[n]*finv[r])%mod)*finv[n-r])%mod; } long long P(int n, int r){ if(n < r)return 0; if(n > n_max)return 0; return (fac[n]*finv[n-r])%mod; } long long H(int n, int r){ return C(n+r-1, r); } }; using comb = Combination; #line 5 "yukicoder-0117.test.cpp" using comb2 = Combination; int main(){ comb2 C(2000010); int q;cin>>q; char _; for(int i = 0; q > i; i++){ char c;cin>>c>>_; int a,b;cin>>a>>_>>b>>_; if(c == 'C')cout << C.C(a,b) << endl; else if(c == 'P')cout << C.P(a,b) << endl; else cout << C.H(a,b) << endl; } }