#include using namespace std; //#pragma GCC optimize("Ofast") #define rep(i,n) for(ll i=0;i=0;i--) #define perl(i,r,l) for(ll i=r-1;i>=l;i--) #define fi first #define se second #define pb push_back #define ins insert #define pqueue(x) priority_queue,greater> #define all(x) (x).begin(),(x).end() #define CST(x) cout<; using vvl=vector>; using pl=pair; using vpl=vector; using vvpl=vector; const ll MOD=1000000007; const ll MOD9=998244353; const int inf=1e9+10; const ll INF=4e18; const ll dy[8]={1,0,-1,0,1,1,-1,-1}; const ll dx[8]={0,1,0,-1,1,-1,1,-1}; template inline bool chmax(T &a, T b) { return ((a < b) ? (a = b, true) : (false)); } template inline bool chmin(T &a, T b) { return ((a > b) ? (a = b, true) : (false)); } int main(){ ll r,k;cin >> r >> k; using ld=long double; vector ans; for(ll x=1;x<=k/2;x++){ ld ok=0,ng=1; rep(_,50){ ld mid=(ok+ng)/2; ld theta=acos(mid); ld sq=theta; sq-=sin(theta)*cos(theta); if(sq>=acos(-1)*x/(k+1))ok=mid; else ng=mid; } //cout << ok << endl; ans.emplace_back(ok); } ll f=ans.size(); rep(i,f)ans.emplace_back(-ans[i]); if(k&1)ans.emplace_back(0); sort(all(ans)); CST(10); for(auto p:ans)cout << p*r << endl; }