# ビット演算なのでビット桁ごとに計算
# 各桁で0が連続している時だけ数えない、あとは、2**d分だけ数える

N = int(input())
A = list(map(int, input().split()))

ans = 0
for d in range(30): # increase to 30
    zeroone = []
    for a in A:
        if a>>d & 1 == 1:
            zeroone.append(1)
        else:
            zeroone.append(0)
    zero_len = 0
    total = N*(N+1)//2
    for i in range(N):
        if zeroone[i] == 0:
            zero_len += 1
        else:
            deduct = zero_len*(zero_len+1)//2
            total -= deduct
            zero_len = 0
    deduct = zero_len*(zero_len+1)//2
    total -= deduct
    calc = pow(2, d)*total
    ans += calc
    #print('d', d, zeroone, total, calc)
print(ans)