#include <algorithm>
#include <bitset>
#include <complex>
#include <cassert>
#include <deque>
#include <exception>
#include <fstream>
#include <functional>
#include <iomanip>
#include <ios>
#include <iosfwd>
#include <iostream>
#include <istream>
#include <iterator>
#include <limits>
#include <list>
#include <locale>
#include <map>
#include <memory>
#include <math.h>
#include <new>
#include <numeric>
#include <ostream>
#include <queue>
#include <set>
#include <sstream>
#include <stack>
#include <stdexcept>
#include <streambuf>
#include <string>
#include <typeinfo>
#include <utility>
#include <valarray>
#include <vector>
#include<regex>
#include<atcoder/all>
using namespace std;
using ll = long long;
using Graph = vector<vector<int>>;
#define rep(i,x) for(ll i=0;i<(ll)(x);i++)
#define rrep(i,x) for(ll i=1;i<=(ll)(x);i++)
#define all(v) v.begin(),v.end()
typedef pair<int, int> pii;
ll mod998 = 998244353;
ll mod109 = 1e9 + 7;
//vector<vector<int>> a(n,vector<int>(n));



using mint = atcoder::modint998244353;
//必要なパラメータ
int my_level = 1;
int my_now = 12;
int point = 0;
int sum = 0;

//盤面情報
int h = 60;
int w = 25;

//power[i][j]…i,jにいる敵の現在の耐久力とパワー(first...耐久力 second...パワー)
vector<vector<pii>> power(h, vector<pii>(w));
//aim...各列で一番下方にあるやつ
vector<pii> aim(25);

//string ans...i文字目はi回目の動作
string ans = "";

//盤面の更新
void reload(int n) {
    
    for (int i = 1; i < 60; i++) {

        for (int j = 0; j < 25; j++) {

            power[i - 1][j] = power[i][j];
            power[i][j] = { 0,0 };
        }

    }

    for (int i = 0; i < n; i++) {

        int t, p, x;
        cin >> t >> p >> x;
        
        power[59][x] = { t,p };

    }

    for (int j = 0; j < 25; j++) {
        aim[j] = { 0,0 };
        for (int i = 0; i < 60; i++) {

            if (power[i][j] != make_pair(0, 0)) {

                aim[j] = power[i][j];
                break;
            }
        }
    }

}

void destination() {
    int ret = 1e9;
    for (int j = 0; j < 25; j++) {
        int k = abs(my_now - j) + 1;
    }

}

int main() {

            
    for (int i = 0; i < 1000; i++) {

        int n;
        cin >> n;
        if (n == -1) {
            return 0;
        }
        reload(n);
        destination();

        if (ans.size() >= i+1) {
            cout << ans[i] << endl;
        }

        cout << "S" << endl;
    }

    
}