#include #include #include #define rep(i, l, r) for(ll i = (l); i <= (r); i++) #define rrep(i, l, r) for(ll i = (r); i >= (l); i--) #define ff first #define ss second #define pb push_back #define ALL(a) (a).begin(),(a).end() typedef long long ll; const int INF32 = 2147483647; const ll INF64 = 9223372036854775807ll; const int MAX=5100000; using namespace std; using namespace atcoder; const ll MOD=998244353ll; using mint = modint998244353; // aよりもbが大きいならばaをbで更新する // (更新されたならばtrueを返す) template bool chmax(T &a, const T& b) { if (a < b) { a = b; // aをbで更新 return true; } return false; } // aよりもbが小さいならばaをbで更新する // (更新されたならばtrueを返す) template bool chmin(T &a, const T& b) { if (a > b) { a = b; // aをbで更新 return true; } return false; } //cin, cout void CIN() {}; template void CIN(T &&x, U &&...y) { cin >> x; CIN(forward(y)...); } void _COUT() { cout << '\n'; } template void _COUT(T &&x, U &&...y) { cout << ' ' << x; _COUT(forward(y)...); } void COUT() { _COUT(); }; template void COUT(T &&x, U &&...y) { cout << x; _COUT(forward(y)...); } vector fact, fact_inv, inv; /* init_nCk :二項係数のための前処理 計算量:O(n) */ void init_nCk(int SIZE) { fact.resize(SIZE + 5); fact_inv.resize(SIZE + 5); inv.resize(SIZE + 5); fact[0] = fact[1] = 1; fact_inv[0] = fact_inv[1] = 1; inv[1] = 1; for (int i = 2; i < SIZE + 5; i++) { fact[i] = fact[i - 1] * i % MOD; inv[i] = MOD - inv[MOD % i] * (MOD / i) % MOD; fact_inv[i] = fact_inv[i - 1] * inv[i] % MOD; } } /* nCk :MODでの二項係数を求める(前処理 int_nCk が必要) 計算量:O(1) */ long long nCk(int n, int k) { assert(!(n < k)); assert(!(n < 0 || k < 0)); return fact[n] * (fact_inv[k] * fact_inv[n - k] % MOD) % MOD; } bool check_grid(ll x, ll y, ll H, ll W){ if(x < 0 || H <= x){return false;} else if(y < 0 || W <= y){return false;} return true; } int main() { cin.tie(0); ios::sync_with_stdio(false); ll X, Y, Z, W; cin >> X >> Y >> Z >> W; init_nCk(1000000); mint ans; if(Z == 0){ans = nCk(X+Y-Z-W-1, Y-W);} else{ans = nCk(X+Y-Z-W-1, X-Z);} for(ll i = X; i > Z; i--){ans *= i;} for(ll i = Y; i > W; i--){ans *= i;} cout << ans.val() << endl; return 0; }