// #pragma GCC target("avx")
// #pragma GCC optimize("O3")
// #pragma GCC optimize("unroll-loops")

#include <bits/stdc++.h>
using namespace std;

#define rep(i,n) for(int i = 0; i < (int)n; i++)
#define FOR(n) for(int i = 0; i < (int)n; i++)
#define repi(i,a,b) for(int i = (int)a; i < (int)b; i++)
#define all(x) x.begin(),x.end()
//#define mp make_pair
#define vi vector<int>
#define vvi vector<vi>
#define vvvi vector<vvi>
#define vvvvi vector<vvvi>
#define pii pair<int,int>
#define vpii vector<pair<int,int>>

template<typename T>
bool chmax(T &a, const T b) {if(a<b) {a=b; return true;} else {return false;}}
template<typename T>
bool chmin(T &a, const T b) {if(a>b) {a=b; return true;} else {return false;}}

using ll = long long;
using ld = long double;
using ull = unsigned long long;

const ll INF = numeric_limits<long long>::max() / 2;
const ld pi = 3.1415926535897932384626433832795028;
const ll mod = 998244353;
int dx[] = {1, 0, -1, 0, -1, -1, 1, 1};
int dy[] = {0, 1, 0, -1, -1, 1, -1, 1};

#define int long long

void solve() {
    const int MX = 5001;
    int n;
    cin >> n;
    vi a(n);
    FOR(n) cin >> a[i];
    if(n == 2) {
        cout << (a[0] == 0 && a[1] == 0? "Yes" : "No") << endl;
        return;
    }
    int XOR = 0;
    vi cnt(MX);
    for(auto e : a) {
        ++cnt[e];
        XOR ^= e;
    }
    if(XOR != 0) {
        cout << "No" << endl;
        return;
    }
    for(auto e : cnt) if(e >= 2) {
        cout << "Yes" << endl;
        return;
    }

    vvi dp(2, vi(1<<15, 0));
    dp[0][0] = 1;
    rep(i, n) {
        int cur = i&1;
        int nxt = 1-cur;
        dp[nxt] = dp[cur];
        rep(j, 1<<15) {
            dp[nxt][j ^ a[i]] += dp[cur][j];
            chmin(dp[nxt][j ^ a[i]], 3LL);
        }
    }
    cout << (dp[n&1][0]>2? "Yes" : "No") << endl;
}

signed main() {
    cin.tie(nullptr);
    ios::sync_with_stdio(false);
    solve();
    return 0;
}