#include #include using namespace std; using namespace atcoder; using mint = modint998244353; const int mod = 998244353; //using mint = modint1000000007; //const int mod = 1000000007; //const int INF = 1e9; //const long long LINF = 1e18; #define rep(i, n) for (int i = 0; i < (n); ++i) #define rep2(i,l,r)for(int i=(l);i<(r);++i) #define rrep(i, n) for (int i = (n-1); i >= 0; --i) #define rrep2(i,l,r)for(int i=(r-1);i>=(l);--i) #define all(x) (x).begin(),(x).end() #define allR(x) (x).rbegin(),(x).rend() #define P pair template inline bool chmax(A & a, const B & b) { if (a < b) { a = b; return true; } return false; } template inline bool chmin(A & a, const B & b) { if (a > b) { a = b; return true; } return false; } int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int p1, p2, q1, q2, t; cin >> p1 >> p2 >> q1 >> q2 >> t; mint p = (mint)p1 / p2; mint q = (mint)q1 / q2; vector dp(t + 1, vector(t + 1)); dp[0][0] = 1; rep(i, t) { rep(j, t + 1) { if (0 == dp[i][j])continue; mint q2 = pow_mod(q.val(), j + 1, mod); int ni = i + 1; dp[i + 1][0] += dp[i][j] * p; dp[i + 1][j + 1] += dp[i][j] * q2; } } mint ans = 0; rep(i, t + 1)ans += dp[t][i]; cout << ans.val() << endl; return 0; }