#include #include using namespace std; using namespace atcoder; using ll = long long; using ld = long double; int N, G[1010], D[1010]; int ma = 0, idx = -1; int main() { cin >> N; for (int i = 0; i < N; i++) { cin >> G[i] >> D[i]; if (ma < G[i] - 30000 * D[i]) { ma = G[i] - 30000 * D[i]; idx = i; } } if (ma * 6 >= 3000000) { cout << "YES" << endl; for (int i = 0; i < 6; i++) { cout << idx + 1 << endl; } } else { cout << "NO" << endl; } return 0; }