#include #include namespace neguse {} using namespace std; using namespace atcoder; using namespace neguse; typedef long long ll; typedef long double ld; typedef pair pii; typedef pair pll; typedef vector vi; typedef vector vll; typedef vector vld; typedef vector vvi; typedef vector vvll; typedef vector vs; typedef vector vpii; typedef vector vpll; #define _overload3(_1,_2,_3,name,...) name #define _rep(i,n) repi(i,0,n) #define repi(i,a,b) for(int i=int(a);iint(b);--i) #define rrep(...) _overload3(__VA_ARGS__,rrepi,_rrep)(__VA_ARGS__) #define _each1(i,v) for(auto& i:v) #define _each2(i,j,v) for(auto& [i,j]:v) #define each(...) _overload3(__VA_ARGS__,_each2,_each1,)(__VA_ARGS__) #define all(x) (x).begin(),(x).end() #define rall(x) (x).rbegin(),(x).rend() #define SORT(x) sort(all(x)) #define RSORT(x) sort(rall(x)) #define REVERSE(x) reverse(all(x)) #define dump(x) cerr << #x << " = " << (x) << '\n' #define print(x) cout << (x) << '\n' #define yes(f) cout << ((f) ? "Yes" : "No") << '\n' #define ge(v, x) (int)(lower_bound(all(v), x) - v.begin()) #define gt(v, x) (int)(upper_bound(all(v), x) - v.begin()) #define le(v, x) (int)(upper_bound(all(v), x) - v.begin())-1 #define lt(v, x) (int)(lower_bound(all(v), x) - v.begin())-1 templatebool chmax(T &a, const T &b) { if (abool chmin(T &a, const T &b) { if (b istream& operator>>(istream& is, vector& vec) { for (T& x : vec) is >> x; return is; } template ostream& operator<<(ostream& os, const vector& vec) { for (const T& x : vec) os << x << ' '; return os; } using namespace neguse; int main() { int N, M, K; cin >> N >> M >> K; vector A(N, vi(M)); rep(i, N) rep(j, M) cin >> A[i][j]; int di[] = {0, 1, 0, -1}; int dj[] = {1, 0, -1, 0}; auto isOK = [&](int x) { // 01-BFS vector dist(N, vi(M, 1e9)); deque dq; dq.emplace_back(0, 0); dist[0][0] = A[0][0] < x; while (!dq.empty()) { auto [i, j] = dq.front(); dq.pop_front(); rep(k, 4) { int ni = i + di[k], nj = j + dj[k]; if (ni < 0 || ni >= N || nj < 0 || nj >= M) continue; int cost = A[ni][nj] < x; if (chmin(dist[ni][nj], dist[i][j] + cost)) { if (cost == 0) dq.emplace_front(ni, nj); else dq.emplace_back(ni, nj); } } } return dist[N - 1][M - 1] <= K; }; int ok = 0, ng = 1e9 + 1; while (abs(ok - ng) > 1) { int mid = ok + (ng - ok) / 2; if (isOK(mid)) ok = mid; else ng = mid; } cout << ok << endl; return 0; }