#include using namespace std; using ll = long long; void solve() { int N, K; ll X; cin >> N >> K >> X; vector H(N), d(N); for(int i = 0; i < N; i++) { cin >> H[i]; } for(int i = 1; i < N; i++) { d[i] = H[i] - H[i - 1]; } string ans = "Yes"; for(int r = 0; r < K; r++) { if(r == 0 && r == N % K) { for(int m = 0; r + K * m < N; m++) { ll hm = (d[r + K * m] % X + X * 1000000000) % X; if(hm != 0) ans = "No"; } }else if(r == 0) { for(int m = (N - r) / K; r + K * m >= 1; m--) { ll hm = (d[r + K * m] % X + X * 1000000000) % X; if(hm != 0) ans = "No"; else if(d[r + K * m] < 0) ans = "No"; else if(r + K * (m - 1) >= 1) d[r + K * (m - 1)] += d[r + K * m]; } }else if(r == N % K) { for(int m = 0; r + K * m < N; m++) { ll hm = (d[r + K * m] % X + X * 1000000000) % X; if(hm != 0) ans = "No"; else if(d[r + K * m] > 0) ans = "No"; else if(r + K * (m + 1) < N) d[r + K * (m + 1)] += d[r + K * m]; } }else { for(int m = 0; r + K * m < N; m++) { ll hm = (d[r + K * m] % X + X * 1000000000) % X; if(hm != 0) ans = "No"; else if(d[r + K * m] > 0) ans = "No"; else if(r + K * (m + 1) < N) d[r + K * (m + 1)] += d[r + K * m]; } if(d[r + K * ((N - r) / K)] != 0) ans = "No"; } // cout << r << " : " << ans << "\n"; } cout << ans << "\n"; } int main() { int T; cin >> T; while(T--) solve(); }