#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include <bits/stdc++.h>
#if __has_include(<atcoder/all>)
#include <atcoder/all>
using namespace atcoder;
#endif
#include <chrono>
#include <unistd.h>
using namespace std;
using namespace chrono;
#define rep(i, n) for (ll i = 0; i < (n); ++i)
#define rep1(i, n) for (ll i = 1; i <= (n); ++i)
#define rrep(i, n) for (ll i = n; i > 0; --i)
#define bitrep(i, n) for (ll i = 0; i < (1 << n); ++i)
#define all(a) (a).begin(), (a).end()
#define yesNo(b) ((b) ? "Yes" : "No")
using ll = long long;
using ull = unsigned long long;
using ld = long double;
using mint = modint998244353;
using MINT = modint1000000007;
string alphabet = "abcdefghijklmnopqrstuvwxyz";
string ALPHABET = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
constexpr double pi = 3.141592653589793;
constexpr ll smallMOD = 998244353;
constexpr ll bigMOD = 1000000007;
constexpr ll dx[] = {1, 0, -1, 0, 1, -1, -1, 1};
constexpr ll dy[] = {0, 1, 0, -1, 1, 1, -1, -1};
struct Init
{
    Init()
    {
        ios::sync_with_stdio(0);
        cin.tie(0);
        cout << fixed << setprecision(15);
    }
} init;
template <typename T>
ostream &operator<<(ostream &os, const vector<T> &vec)
{
    os << "[";
    rep(i, vec.size())
    {
        os << vec[i];
        if (i != vec.size() - 1)
            os << ", ";
    }
    os << "]";
    return os;
}
template <typename T>
ostream &operator<<(ostream &os, const vector<vector<T>> &vec)
{
    os << "[";
    rep(i, vec.size())
    {
        os << vec[i];
        if (i != vec.size() - 1)
            os << ", ";
    }
    os << "]";
    return os;
}

// graph_template
struct Edge
{
    ll to;
    ll cost;
    Edge(ll to, ll cost) : to(to), cost(cost) {}
    bool operator>(const Edge &e) const
    {
        return cost > e.cost;
    }
};

int main()
{
    ll n, m, k;
    cin >> n >> m >> k;
    vector<vector<ll>> mp(n, vector<ll>(m, 0));
    rep(i, n)
    {
        rep(j, m)
        {
            cin >> mp[i][j];
        }
    }
    vector<vector<ll>> dist(n + m - 1);
    rep(i, n)
    {
        rep(j, m)
        {
            dist[i + j].push_back(mp[i][j]);
        }
    }
    vector<ll> ans;
    rep(i, n + m - 1)
    {
        ans.push_back(*max_element(all(dist[i])));
    }
    sort(all(ans));
    rep(i, k)
    {
        ans[i] = 1000000000;
    }
    cout << *min_element(all(ans)) << endl;
    return 0;
}